Asp.net webMethodからAjax呼び出しにJsonオブジェクトを返す

Question

次のAjax呼び出しメソッドとasp.net webmethodがあります。

私のasp.net関数は、Ajax呼び出しで必要な値を返しています。

私は多くのことを試しましたが、まだ成功していません。

AJAX CALL

<script type="text/javascript">


        $(document).ready(function () {
            // Add the page method call as an onclick handler for the control.
            $("#<%=ddlEmailTemplate.ClientID%>").change(function () {
                debugger;
                var myparam = $("#<%=ddlEmailTemplate.ClientID%>").val(); //id name for dropdown list
                $.ajax({
                    type: "POST",
                    url: "FileTax.aspx/ddlEmailTemplate_SelectedIndexChanged",
                    data: '{param:"' + myparam + '"}',
                    contentType: "application/json; charset=utf-8",
                    success: function (data) {
                        alert(data.d)
                    }
                });
            });
        });
    </script>

WebMethod asp.net

回答後に更新

[WebMethod, ScriptMethod(ResponseFormat = ResponseFormat.Json, UseHttpGet = false)]
    public static string ddlEmailTemplate_SelectedIndexChanged(string param)
    {
        string subject;
        string Description;
        using (SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["ForMyTaxConnectionString"].ConnectionString))
        {
            con.Open();
            DataSet ds = new DataSet();
            using (SqlCommand cmd = new SqlCommand())
            {

                cmd.Connection = con;
                cmd.CommandType = CommandType.StoredProcedure;
                cmd.CommandText = "Spo_ShowEmailTemplateContent";
                cmd.Parameters.Add(new SqlParameter("@Tid", SqlDbType.Int)).Value = Convert.ToInt32(param);
                using (SqlDataAdapter da = new SqlDataAdapter(cmd))
                {
                    da.Fill(ds);
                    con.Close();
                    da.Dispose();
                }
                if (ds.Tables[0].Rows.Count > 0)
                {
                    DataRow dr = ds.Tables[0].Rows[0];

                    subject = Convert.ToString(dr["TemplateSubject"]);
                    Description = Convert.ToString(dr["TemplateDescription"]);

                }
            }

        }

        return JsonConvert.SerializeObject(new { subject = subject, description = Description });
        // return subject ;

Answer 1

含むusing Newtonsoft.Json;

[〜＃〜] cs [〜＃〜]

public string CheckDetails(string param1, string param2)
{
  var chk = new check
  {
    subject = "hello! " +param1 ,
    description = param2 +" Years Old"
  };
 return JsonConvert.SerializeObject(chk);
}

public class check
{
  public string subject { get; set; }
  public string description { get; set; }
}

[〜＃〜] html [〜＃〜]

<div> 
     <input type="text" name="name" id="txtname"/>
     <input type="text" name="age" id="txtage"/>
     <input type="button" id="btnSubmit" value="details"/>
</div>

Jquery

$(function () {
            $('#btnSubmit').on('click', function () {
                var options = {
                    type: "POST",
                    url: '/Ajax/CheckDetails/',
                    data: '{param1:"' + $('#txtname').val() + '",param2:"' + $('#txtage').val() + '"}',
                    async: false,
                    cache: false,
                    dataType: "json",
                    contentType: "application/json; charset=utf-8",
                    success: function (response) {
                        if (response != null && response.d != null) {
                            var data = response.d;
                            alert(typeof (data)); //it comes out to be string 
                            //we need to parse it to JSON 
                            data = $.parseJSON(data);
                            alert(data.subject);
                            alert(data.description);
                        }
                    }
                };
                $.ajax(options);
            });
        });