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キー値でJSONをフィルター

次のJSONがあり、配列を同じ形式に保ちたいが、タイプ_"ar"_のオブジェクトのみを含めたい。このJSONをJavaScriptでフィルタリングして、必要なタイプのみを含めるにはどうすればよいですか？

_[{"time":"2016-07-26 09:02:27","type":"aa"},
{"time":"2016-04-21 20:35:07","type":"ae"},
{"time":"2016-08-20 03:31:57","type":"ar"},
{"time":"2017-01-19 22:58:06","type":"ae"},
{"time":"2016-08-28 10:19:27","type":"ae"},
{"time":"2016-12-06 10:36:22","type":"ar"},
{"time":"2016-07-09 12:14:03","type":"ar"},
{"time":"2016-10-25 05:05:37","type":"ae"},
{"time":"2016-06-05 07:57:18","type":"ae"},
{"time":"2016-10-08 22:03:03","type":"aa"},
{"time":"2016-08-13 21:27:37","type":"ae"},
{"time":"2016-04-09 07:36:16","type":"ar"},
{"time":"2016-12-30 17:20:08","type":"aa"},
{"time":"2016-03-11 17:31:46","type":"aa"},
{"time":"2016-05-04 14:08:25","type":"ar"},
{"time":"2016-11-29 05:21:02","type":"ar"},
{"time":"2016-03-08 05:46:01","type":"ar"},
]
_
javascriptarraysjsonobjectfilter
14
JordanBarber

filterメソッドを使用する必要があります。

filter()メソッドは、提供された関数によって実装されたテストに合格したすべての要素を含む新しいarrayを作成します。

提供関数は、配列の各要素に適用されるcallbackです。

var arr=[{"time":"2016-07-26 09:02:27","type":"aa"},
{"time":"2016-04-21 20:35:07","type":"ae"},
{"time":"2016-08-20 03:31:57","type":"ar"},
{"time":"2017-01-19 22:58:06","type":"ae"},
{"time":"2016-08-28 10:19:27","type":"ae"},
{"time":"2016-12-06 10:36:22","type":"ar"},
{"time":"2016-07-09 12:14:03","type":"ar"},
{"time":"2016-10-25 05:05:37","type":"ae"},
{"time":"2016-06-05 07:57:18","type":"ae"},
{"time":"2016-10-08 22:03:03","type":"aa"},
{"time":"2016-08-13 21:27:37","type":"ae"},
{"time":"2016-04-09 07:36:16","type":"ar"},
{"time":"2016-12-30 17:20:08","type":"aa"},
{"time":"2016-03-11 17:31:46","type":"aa"},
{"time":"2016-05-04 14:08:25","type":"ar"},
{"time":"2016-11-29 05:21:02","type":"ar"},
{"time":"2016-03-08 05:46:01","type":"ar"},
];
var filtered=arr.filter(function(item){
    return item.type=="ar";         
});
console.log(filtered);

また、shorterの方法を使用できます。

var filtered = arr.filter(a=>a.type=="ar");
20
Mihai Alexandru-Ionut

filter関数を使用できます。 ブラウザサポート 最初に確認します。

var result = a.filter(function(v){
    return v.type==='ar';
})

お役に立てれば。

var list = [
  {"time":"2016-07-26 09:02:27","type":"aa"},
  {"time":"2016-04-21 20:35:07","type":"ae"},
  {"time":"2016-08-20 03:31:57","type":"ar"},
  {"time":"2017-01-19 22:58:06","type":"ae"},
  {"time":"2016-08-28 10:19:27","type":"ae"},
  {"time":"2016-12-06 10:36:22","type":"ar"},
  {"time":"2016-07-09 12:14:03","type":"ar"},
  {"time":"2016-10-25 05:05:37","type":"ae"},
  {"time":"2016-06-05 07:57:18","type":"ae"},
  {"time":"2016-10-08 22:03:03","type":"aa"},
  {"time":"2016-08-13 21:27:37","type":"ae"},
  {"time":"2016-04-09 07:36:16","type":"ar"},
  {"time":"2016-12-30 17:20:08","type":"aa"},
  {"time":"2016-03-11 17:31:46","type":"aa"},
  {"time":"2016-05-04 14:08:25","type":"ar"},
  {"time":"2016-11-29 05:21:02","type":"ar"},
  {"time":"2016-03-08 05:4601","type":"ar"},
];

var result = list.filter(function(obj, index){
  return obj.type==='ar';
})

console.log(result);
2
Zakaria Acharki

filterメソッドを使用すると、特定の条件に一致する要素のみを返すように配列をフィルタリングできますdata.filter((x)=>x.type === "ar");

filterメソッドは、条件x.type === "ar"を渡すすべての要素を含む新しい配列を作成します

var data =[{"time":"2016-07-26 09:02:27","type":"aa"},
{"time":"2016-04-21 20:35:07","type":"ae"},
{"time":"2016-08-20 03:31:57","type":"ar"},
{"time":"2017-01-19 22:58:06","type":"ae"},
{"time":"2016-08-28 10:19:27","type":"ae"},
{"time":"2016-12-06 10:36:22","type":"ar"},
{"time":"2016-07-09 12:14:03","type":"ar"},
{"time":"2016-10-25 05:05:37","type":"ae"},
{"time":"2016-06-05 07:57:18","type":"ae"},
{"time":"2016-10-08 22:03:03","type":"aa"},
{"time":"2016-08-13 21:27:37","type":"ae"},
{"time":"2016-04-09 07:36:16","type":"ar"},
{"time":"2016-12-30 17:20:08","type":"aa"},
{"time":"2016-03-11 17:31:46","type":"aa"},
{"time":"2016-05-04 14:08:25","type":"ar"},
{"time":"2016-11-29 05:21:02","type":"ar"},
{"time":"2016-03-08 05:46:01","type":"ar"},
];
           
var result = data.filter((x)=>x.type === "ar");
console.log(result);
1
Abhinav Galodha

上記の答えほどきれいではありませんが、それでも仕事をします

var list = [{"time":"2016-07-26 09:02:27","type":"aa"},
{"time":"2016-04-21 20:35:07","type":"ae"},
{"time":"2016-08-20 03:31:57","type":"ar"},
{"time":"2017-01-19 22:58:06","type":"ae"},
{"time":"2016-08-28 10:19:27","type":"ae"},
{"time":"2016-12-06 10:36:22","type":"ar"},
{"time":"2016-07-09 12:14:03","type":"ar"},
{"time":"2016-10-25 05:05:37","type":"ae"},
{"time":"2016-06-05 07:57:18","type":"ae"},
{"time":"2016-10-08 22:03:03","type":"aa"},
{"time":"2016-08-13 21:27:37","type":"ae"},
{"time":"2016-04-09 07:36:16","type":"ar"},
{"time":"2016-12-30 17:20:08","type":"aa"},
{"time":"2016-03-11 17:31:46","type":"aa"},
{"time":"2016-05-04 14:08:25","type":"ar"},
{"time":"2016-11-29 05:21:02","type":"ar"},
{"time":"2016-03-08 05:46:01","type":"ar"},
]

var newList = [];

for (var i = 0; i < list.length; i++) {
    if (list[i].type === 'ar') {
        newList.Push(list[i]);
    }
}

console.log(newList);
0
user2085143