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jsonファイル形式の配列に項目を追加する方法

1つのデータのみを使用してjsonファイルに挿入しています。

$data=$_POST['myusernamer'];

$inp = file_get_contents('7players.json');
$tempArray = json_decode($inp);
array_Push($tempArray, $data);
$jsonData = json_encode($tempArray);
file_put_contents('7players.json', $jsonData);

これが私のjsonファイルの外観です。最後に1人追加したいだけです。

{ 

"players":[
   {

        "name":"Moldova",
        "image":"/Images/Moldova.jpg",
        "roll_over_image":"tank.jpg"
   },
   {

        "name":"Georgia",
        "image":"/Images/georgia.gif",
        "roll_over_image":"tank.jpg"
   },
   {

        "name":"Belarus",
        "image":"/Images/Belarus.gif",
        "roll_over_image":"tank.jpg" 
   },
   {

        "name":"Armenia",
        "image":"/Images/armenia.png",
        "roll_over_image":"tank.jpg"
   },
   {

        "name":"Kazahstan",
        "image":"/Images/kazahstan.gif",
        "roll_over_image":"tank.jpg"
   },
   {

        "name":"Russia",
        "image":"/Images/russia.gif",
        "roll_over_image":"tank.jpg"
   },
  ],


"games" : [ 

    { 

    "matches" : [ 

            {

            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },

            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },

            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },

            {
            "player1id":"*",
            "player2id":7,
            "winner":"*"
            },

            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },

            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },

            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            }
        ]
       },

    {

    "matches" : [

            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },
            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },
            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },
            {
            "player1id":"*",
            "player2id":7,
            "winner":"*"
            },
            {           
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },
            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },
            {
            "player1id":"*",
            "player2id":"*",
            "winner":"*"
            },

      ]
    }
  ] 
}

私の質問は、最後にプレーヤーを追加するにはどうすればよいですか？更新方法も知りたい

player1id":"*",
"player2id":"*",
"winner":"

マッチ配列内。

phpjsonfilepost
13
user2234992

Json文字列をデコードしてから、配列Pushを使用するだけです

$tempArray = json_decode($jsonstring, true);
array_Push($tempArray, $your_data);

あなたの場合

    $str = '{ 

"players":[
   {

        "name":"Moldova",
        "image":"/Images/Moldova.jpg",
        "roll_over_image":"tank.jpg"
   },
   {

        "name":"Georgia",
        "image":"/Images/georgia.gif",
        "roll_over_image":"tank.jpg"
   } ]}';


 $arr = json_decode($str, true);
 $arrne['name'] = "dsds";
 array_Push( $arr['players'], $arrne );
 print_r($arr);

Print_r（$ arr）;の値を確認するだけです。これがあなたの望むものであることを願っています。 :)

15
chandresh_cool

別のプレーヤーを追加する

$tempArray = json_decode($inp, true);
array_Push($tempArray['players'], array('name' => $data['username'], 'image' => $data['userimage'], 'roll_over_image' => 'tank.jpg'));

試合の更新

最初の一致配列

$tempArray['games'][0]['matches'];

2番目の一致配列

$tempArray['games'][1]['matches'];

は、キーplayer1id、player2id、およびwinnerを持つ単純な2次元配列になりました-これらの更新は簡単です。その後、$tempArrayをエンコードしてjsonに戻すことができます。

7
slash197
<html>
<head>
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
    <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.3.min.js" ></script>
</head>
<body>
    <?php
       //first copy your json data  data.json
        $str = file_get_contents('data.json');//get contents of your json file and store it in a string,bro small suggestion never keep any JSON data in ur html file its not safe.always keep json data in external file.
        $arr = json_decode($str, true);//decode it
         $arrne['players'] = "sadaadad";
         $arrne['image'] = "sadaadad";
         $arrne['roll_over_image'] = "sadaadad";
         array_Push( $arr['employees'], $arrne);//Push contents to ur decoded array i.e $arr
         $str = json_encode($arr);
        //now send evrything to ur data.json file using folowing code
         if (json_decode($str) != null)
           {
             $file = fopen('data.json','w');
             fwrite($file, $str);
             fclose($file);
           }
           else
           {
             //  invalid JSON, handle the error 
           }

        ?>
</body>
2
sudheer suri

コアPHP

jSON応答の配列が必要な場合。次に、このコードで行くことができます。

非常に簡単な方法で、これらの手順を使用できます。

1）json_decode（）を使用してJSONを配列に変換する必要がある手順。

2）新しい配列を追加するには、array_merge（）メソッドを使用します。配列を追加したい場合。

$staff =  json_decode($staffRes ,true);
$driver = ["helpers"=>[id=>1,name=>hep1],[id=>2,name=>hep2]]
$profile= array_merge($staff ,$driver );

ララヴェルで

$staff =  collect($staffRes)->toArray() ; // json() also work here.
$driver = ["helpers"=>[id=>1,name=>hep1],[id=>2,name=>hep2]]
$profile= array_merge($staff ,$driver );

出力

{
    "error": 0,
    "errmsg": "",
    "response": {
        "id": "NlF4VDMrdEoxM2RCUWkxUE92c29tZz09",
        "type": "DRIVER",
        "driver_name": "Ravi Kumar",     
        "route_name": "Barasat Dak Bungalow",
        "helpers": [
            {
                "helper_id": "K09NTlpHMStiNGlKSGZNMUIyWlAxZz09",
                "helper_name": "Arvind Kumar",
                "helper_mobile": "7777777775",
                "helper_alt_mobile": "7777777777",
                "birth_date": "01-10-2000",
                "address": "Bongaon",
                "id_proof": "123456789-WB",
                "licence_no": null,
                "experience": "2-year",
                "helper_photo":""
            },
            {
                "helper_id": "K29la21vY0VnMTZ5cFY2MU02cm1ZUT09",
                "helper_name": "SUBIR DAS",
                "helper_mobile": "5555555555",
                "helper_alt_mobile": "5555555554",
                "birth_date": "30-10-2019",
                "address": "610/8, ....",
                "id_proof": "NA",
                "licence_no": "NA",
                "experience": "2 years",
                "helper_photo": ""
            }
        ]
    }
}
0
pankaj kumar