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2つのSQLクエリに参加する

2つのSQLクエリがあります。最初のクエリは次のとおりです。

select Activity, SUM(Amount) as "Total Amount 2009"
from Activities, Incomes
where Activities.UnitName = ? AND
      Incomes.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;

2番目は次のとおりです。

select Activity, SUM(Amount) as "Total Amount 2008"
from Activities, Incomes2008
where Activities.UnitName = ? AND
      Incomes2008.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;

（ '？'を気にしないでください、それらはbirtのパラメーターを表します）。私が達成したいのは次のとおりです：最初のクエリと同じを返すが、「合計金額2008」（2番目のクエリから）のように見える追加の（3番目の）列を持つSQLクエリが必要です。

sqldatabasejoin
29
anon

一部のDBMSは、FROM (SELECT ...) AS alias_name構文をサポートしています。

2つの元のクエリを一時テーブルと考えてください。次のようにクエリできます：

SELECT t1.Activity, t1."Total Amount 2009", t2."Total Amount 2008"
FROM (query1) as t1, (query2) as t2
WHERE t1.Activity = t2.Activity
46
Liam
SELECT Activity, arat.Amount "Total Amount 2008", abull.Amount AS "Total Amount 2009"
FROM
  Activities a
LEFT OUTER JOIN
  (
  SELECT ActivityId, SUM(Amount) AS Amount
  FROM Incomes ibull
  GROUP BY
    ibull.ActivityId
  ) abull
ON abull.ActivityId = a.ActivityID
LEFT OUTER JOIN
  (
  SELECT ActivityId, SUM(Amount) AS Amount
  FROM Incomes2008 irat
  GROUP BY
    irat.ActivityId
  ) arat
ON arat.ActivityId = a.ActivityID
WHERE a.UnitName = ?
ORDER BY Activity
16
Quassnoi

nion を使用します

2番目のクエリで追加の列名を追加し、''他のクエリの対応するすべての場所

例

//reverse order to get the column names
select top 10 personId, '' from Telephone//No Column name assigned 
Union 
select top 10 personId, loanId from loan
11
cgreeno

ここに私のために働いたものがあります：

select visits, activations, simulations, simulations/activations
   as sims_per_visit, activations/visits*100
   as adoption_rate, simulations/activations*100
   as completion_rate, duration/60
   as minutes, m1 as month, Wk1 as week, Yr1 as year 

from
(
    (select count(*) as visits, year(stamp) as Yr1, week(stamp) as Wk1, month(stamp)
    as m1 from sessions group by week(stamp), year(stamp)) as t3

    join

    (select count(*) as activations, year(stamp) as Yr2, week(stamp) as Wk2,
    month(stamp) as m2 from sessions where activated='1' group by week(stamp),
    year(stamp)) as t4

    join

    (select count(*) as simulations, year(stamp) as Yr3 , week(stamp) as Wk3,
    month(stamp) as m3 from sessions where simulations>'0' group by week(stamp),
    year(stamp)) as t5

    join

    (select avg(duration) as duration, year(stamp) as Yr4 , week(stamp) as Wk4,
    month(stamp) as m4 from sessions where activated='1' group by week(stamp),
    year(stamp)) as t6
)
where Yr1=Yr2 and Wk1=Wk2 and Wk1=Wk3 and Yr1=Yr3 and Yr1=Yr4 and Wk1=Wk4

結合ではなく結合を使用しました（クエリごとに異なる列が必要で、結合ではすべてが同じ列に配置されます）。

ありがとう！私はこのページなしでそれを引き出すことができなかったでしょう！ PS：申し訳ありませんが、文を色でフォーマットする方法がわかりません。等.

2
Haitham Alhumsi

これを試して：

select Activity, SUM(Incomes.Amount) as "Total Amount 2009", SUM(Incomes2008.Amount) 
as "Total Amount 2008" from
Activities, Incomes, Incomes2008
where Activities.UnitName = ?  AND
Incomes.ActivityId = Activities.ActivityID  AND
Incomes2008.ActivityId = Activities.ActivityID GROUP BY
Activity ORDER BY Activity;

基本的に、最初のクエリの出力でIncomes2008テーブルを結合する必要があります。

1
Shivasubramanian A

両方の年のすべてのアクティビティに値が存在すると仮定する場合、次のように内部結合を行うだけです

 select act.activity, t1.amount as "Total 2009", t2.amount as "Total 2008"
from Activities as act,
    (select activityid,  SUM(Amount) as amount
    from Activities, Incomes
    where Activities.UnitName = ? AND
          Incomes.ActivityId = Activities.ActivityID
    GROUP BY Activityid) as t1,
    (select activityid, SUM(Amount) as amount
    from Activities, Incomes2008
    where Activities.UnitName = ? AND
          Incomes2008.ActivityId = Activities.ActivityID
    GROUP BY Activityid) as t2
    WHERE t1.activityid= t2.activityid
    AND act.activityId = t1.activityId
    ORDER BY act.activity

これを想定できない場合は、外部結合の実行を見てください

1
Il-Bhima

おそらくこれを解決する最もエレガントな方法ではありません

select  Activity, 
        SUM(Amount) as "Total_Amount",
        2009 AS INCOME_YEAR
from    Activities, Incomes
where Activities.UnitName = ? AND
      Incomes.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;

UNION

select  Activity, 
        SUM(Amount) as "Total_Amount",
        2008 AS INCOME_YEAR
from Activities, Incomes2008
where Activities.UnitName = ? AND
      Incomes2008.ActivityId = Activities.ActivityID
GROUP BY Activity
ORDER BY Activity;
1
Natrium