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複数の共通テーブル式を結合する

2つのクエリQuery1があります。

with cte as (
select
        dbo.Cable.*,
        row_number() over(partition by dbo.Cable.TagNo order by dbo.Cable.CableRevision desc) as rn
    from dbo.Cable 
    where (dbo.Cable.CableRevision = @CoreRevision )  
    )
select *
from cte
where rn = 1

また、Query2

with cte as (
select
        dbo.Cable.TagNo,dbo.Core.*,
        row_number() over(partition by dbo.Core.CoreNo order by dbo.Core.CoreRevision desc) as rn
    from dbo.Core INNER JOIN 
     dbo.Cable ON dbo.Cable.Id = dbo.Core.CableId
    where  (dbo.Core.CoreRevision <= @CoreRevision  )
    )
select *
from cte
where rn = 1

これら2つのクエリはQuery1.TagNoおよびQuery2.TagNoこれら2つのクエリを結合するにはどうすればよいですか。Withコマンドを使用してそれを行うことはできますか？

ありがとうございました

sqlsql-server-2008tsqlcommon-table-expression
17
nnmmss

このクエリを試してください。おそらくこれがあなたが探しているものです。

;WITH cte AS
 (SELECT dbo.Cable.*, 
         row_number() over(partition by dbo.Cable.TagNo order by dbo.Cable.CableRevision desc) as rn
  FROM dbo.Cable 
  WHERE dbo.Cable.CableRevision = @CoreRevision
  ), cte2 AS
 (SELECT dbo.Cable.TagNo, dbo.Core.*, 
         row_number() over(partition by dbo.Core.CoreNo order by dbo.Core.CoreRevision desc) as rn
  FROM dbo.Core INNER JOIN dbo.Cable ON dbo.Cable.Id = dbo.Core.CableId
  WHERE dbo.Core.CoreRevision <= @CoreRevision
  )
  SELECT *
  FROM cte c FULL JOIN cte2 c2 ON c.TagNo = c2.TagNo
  WHERE c.rn = 1 OR c2.rn = 1
21
Aleksandr Fedorenko
with cte as 
(
    select
        dbo.Cable.*,
        row_number() over(partition by dbo.Cable.TagNo order by dbo.Cable.CableRevision desc) as rn
    from dbo.Cable 
    where (dbo.Cable.CableRevision = @CoreRevision )  
), 
cte2 as (
    select
        dbo.Cable.TagNo,dbo.Core.*,
        row_number() over(partition by dbo.Core.CoreNo order by dbo.Core.CoreRevision desc) as rn
    from dbo.Core INNER JOIN 
     dbo.Cable ON dbo.Cable.Id = dbo.Core.CableId
    where  (dbo.Core.CoreRevision <= @CoreRevision  )
    )
select *
from cte
  join cte2 on cte1.TagNo = cte2.TagNo
where cte.rn = 1 and cte2.rn = 1;

条件cte.rn = 1 and cte2.rn = 1が適切かどうかはわかりません。たぶん、どちらか一方のCTEでそれが必要な場合もあれば、両方の場合もあるでしょう。実際には、結合条件にcte2.rn = 1を使用した外部結合が必要な場合もあります...

6
a_horse_with_no_name